Wed, 15 Jun 2005 07:46:40 -0600
Mike Hansen <mhansen (AT) cso (DOT) atmel.comwrote:

Subject:
Re: [Tutor] Controlling Where My Program Ends
From:
Don Parris <webdev (AT) matheteuo (DOT) org>
Date:
Tue, 14 Jun 2005 23:03:59 -0400
To:
tutor (AT) python (DOT) org

To:
tutor (AT) python (DOT) org

Wed, 15 Jun 2005 00:59:24 -0000
"DC Parris" <webdev (AT) matheteuo (DOT) orgwrote:


>>Never mind. I found it - sys.exit()
>>
>>Sorry to have wasted the bandwidth/time.

This was in reference to a post about exiting from a program. I
couldn't figure out why my program wouldn't let me exit from within a
sub-menu of the console interface. Since my webmail client goofed up
the "from" header, it never showed up, and I've cancelled it to avoid
wasting everyone's time further. I found sys.exit() in the library
reference, which allows me to do what I want.

Don

If you use the if __name__ == '__main__': idiom, then you can just use
return instead of sys.exit()

def main():
lotsa interesting python code
if somethinorother:
# sys.exit()
return
more interesting python code

if __name__ == '__main__':
main()

Thanks. I'll try that out a little later (when I get back to this).
Incidentally, my menu system started off quite klunky, but I've thrown my
menu items into dictionaries and iterate through them to display the menu.
Thus, instead of:
print 'menuitem'
print 'menuitem'
etc., etc., etc.

I now have:
for i in menu.iteritems():
print repr(key), '', 'value'

Now if I can figure out how to iterate through the if elif statements,
I'll be able to shorten the code a bit further. First things first though.
Let me just understand these basic things, and then I'll see if I can get a
little smarter.

Maybe I'll start a thread "trials of a Python newbie". It'll be hilarious
for the old timers, I'm sure. It might help other newbies as well.

Don