I have a regular for loop - for($i=1; $i<100; $i++)
Within the loop I need to create variables named:
$p1name;
$p2name;
$p3name;
etc.
The integer portion of each variable name needs to be the value of $i.
I can't seem to get my syntax correct?
Can someone point me in the right direction?
Thanks.
Albert Padley

Tuesday 20 June 2006 15:14, Albert Padley wrote:
I have a regular for loop - for($i=1; $i<100; $i++)

Within the loop I need to create variables named:

$p1name;
$p2name;
$p3name;
etc.

The integer portion of each variable name needs to be the value of $i.

I can't seem to get my syntax correct?

Can someone point me in the right direction?

Thanks.

Albert Padley

If you really want to keep the p?name syntax, I would suggest throwing them in
an array with keys.

$arr["p1name"]
$arr["p2name"]

Then that way you can create the key dynamically:

$arr["p".$i."name"]

Not pretty, but it works.

Thanks,

for($i=1; $i<100; $i++) {
${'p'.$i.'name'} = 'whatever';
}
- jeff

20-Jun-06, at 6:14 PM, Albert Padley wrote:

I have a regular for loop - for($i=1; $i<100; $i++)

Within the loop I need to create variables named:

$p1name;
$p2name;
$p3name;
etc.

The integer portion of each variable name needs to be the value of $i.

I can't seem to get my syntax correct?

Can someone point me in the right direction?

Thanks.

Albert Padley

Ray Hauge wrote:
Tuesday 20 June 2006 15:14, Albert Padley wrote:
>I have a regular for loop - for($i=1; $i<100; $i++)
>>
>Within the loop I need to create variables named:
>>
>$p1name;
>$p2name;
>$p3name;
>etc.
>>
>The integer portion of each variable name needs to be the value of $i.
>>
>I can't seem to get my syntax correct?
>>
>Can someone point me in the right direction?
>>
>Thanks.
>>
>Albert Padley

If you really want to keep the p?name syntax, I would suggest throwing them in
an array with keys.

$arr["p1name"]
$arr["p2name"]

Then that way you can create the key dynamically:

$arr["p".$i."name"]

Not pretty, but it works.

Thanks,

I haven't checked this, but couldn't you reference it as $arr["p$iname"]
? Is there a reason why variable expansion wouldn't work in this
circumstance?

If it does, you could make it easier to read by doing $arr["p{$i}name"]
even though the {} aren't required. It'd be a lot easier to read than
concatenations :)

Regards, Adam.

Are you sure that you don't want an array? Arrays are normally much
better for this type of thing.

That said,
${"p{$i}name"} = 'foo';

David

Albert Padley wrote:
I have a regular for loop - for($i=1; $i<100; $i++)

Within the loop I need to create variables named:

$p1name;
$p2name;
$p3name;
etc.

The integer portion of each variable name needs to be the value of $i.

I can't seem to get my syntax correct?

Can someone point me in the right direction?

Thanks.

Albert Padley

Tuesday 20 June 2006 15:28, Adam Zey wrote:
Ray Hauge wrote:
Tuesday 20 June 2006 15:14, Albert Padley wrote:
>I have a regular for loop - for($i=1; $i<100; $i++)
>>
>Within the loop I need to create variables named:
>>
>$p1name;
>$p2name;
>$p3name;
>etc.
>>
>The integer portion of each variable name needs to be the value of $i.
>>
>I can't seem to get my syntax correct?
>>
>Can someone point me in the right direction?
>>
>Thanks.
>>
>Albert Padley
>
If you really want to keep the p?name syntax, I would suggest throwing
them in an array with keys.

$arr["p1name"]
$arr["p2name"]

Then that way you can create the key dynamically:

$arr["p".$i."name"]

Not pretty, but it works.

Thanks,

I haven't checked this, but couldn't you reference it as $arr["p$iname"]
? Is there a reason why variable expansion wouldn't work in this
circumstance?

If it does, you could make it easier to read by doing $arr["p{$i}name"]
even though the {} aren't required. It'd be a lot easier to read than
concatenations :)

Regards, Adam.

Both of those ways work. I think there's a question on the PHP Certification
Exam about the different ways to work with strings.

Thanks everyone. Always nice to know there is more than one direction
to go in.

Albert

Jun 20, 2006, at 4:52 PM, Ray Hauge wrote:

Tuesday 20 June 2006 15:28, Adam Zey wrote:
>Ray Hauge wrote:
Tuesday 20 June 2006 15:14, Albert Padley wrote:
I have a regular for loop - for($i=1; $i<100; $i++)

Within the loop I need to create variables named:

$p1name;
$p2name;
$p3name;
etc.

The integer portion of each variable name needs to be the value
of $i.

I can't seem to get my syntax correct?

Can someone point me in the right direction?

Thanks.

Albert Padley

If you really want to keep the p?name syntax, I would suggest
throwing
them in an array with keys.

$arr["p1name"]
$arr["p2name"]

Then that way you can create the key dynamically:

$arr["p".$i."name"]

Not pretty, but it works.

Thanks,
>>
>I haven't checked this, but couldn't you reference it as $arr["p
>$iname"]
>? Is there a reason why variable expansion wouldn't work in this
>circumstance?
>>
>If it does, you could make it easier to read by doing $arr["p{$i}
>name"]
>even though the {} aren't required. It'd be a lot easier to read than
>concatenations :)
>>
>Regards, Adam.
>
Both of those ways work. I think there's a question on the PHP
Certification
Exam about the different ways to work with strings.

Albert Padley wrote:
Thanks everyone. Always nice to know there is more than one direction
to go in.

A alternative to variable variables might use these:

'extract' looks like it might be right up your alley:

<?php
$vars = array();
for ($i=1; $i<100; $i++) { $vars["p".$i."name"] = $i; }
extract($vars);
?>

Dante

Tuesday 20 June 2006 15:14, Albert Padley wrote:
I have a regular for loop - for($i=1; $i<100; $i++)

Within the loop I need to create variables named:

$p1name;
$p2name;
$p3name;
etc.

The integer portion of each variable name needs to be the value of
$i.

I can't seem to get my syntax correct?

Can someone point me in the right direction?

Thanks.

Albert Padley

Tue, 2006-06-20 at 19:19, Albert Padley wrote:
Thanks everyone. Always nice to know there is more than one direction
to go in.

Albert

Jun 20, 2006, at 4:52 PM, Ray Hauge wrote:

Tuesday 20 June 2006 15:28, Adam Zey wrote:
>Ray Hauge wrote:
Tuesday 20 June 2006 15:14, Albert Padley wrote:
I have a regular for loop - for($i=1; $i<100; $i++)

Within the loop I need to create variables named:

$p1name;
$p2name;
$p3name;
etc.

The integer portion of each variable name needs to be the value
of $i.

I can't seem to get my syntax correct?

Can someone point me in the right direction?

Thanks.

Albert Padley

If you really want to keep the p?name syntax, I would suggest
throwing
them in an array with keys.

$arr["p1name"]
$arr["p2name"]

Then that way you can create the key dynamically:

$arr["p".$i."name"]

Not pretty, but it works.

Thanks,
>>
>I haven't checked this, but couldn't you reference it as $arr["p
>$iname"]
>? Is there a reason why variable expansion wouldn't work in this
>circumstance?
>>
>If it does, you could make it easier to read by doing $arr["p{$i}
>name"]
>even though the {} aren't required. It'd be a lot easier to read than
>concatenations :)
>>
>Regards, Adam.
>
Both of those ways work. I think there's a question on the PHP
Certification
Exam about the different ways to work with strings.

Ahhh, got to love the fact that there's a question, yet no need for the
taker to actually understand the implications. Does anyone know if you
can get toilet paper with certs printed on it?

Cheers,
Rob.