Hi
Am pretty new to python and hence this question
I have file with an output of a process. I need to search this file one
line at a time and my pattern is that I am looking for the lines that
has the word 'event' and the word 'new'.
Note that i need lines that has both the words only and not either one
of them
how do i write a regexp for this or better yet shd i even be using
regexp or is there a better way to do this
thanks

elrondrules (AT) gmail (DOT) com wrote:
Hi

Am pretty new to python and hence this question

I have file with an output of a process. I need to search this file one
line at a time and my pattern is that I am looking for the lines that
has the word 'event' and the word 'new'.

Note that i need lines that has both the words only and not either one
of them

how do i write a regexp for this or better yet shd i even be using
regexp or is there a better way to do this

thanks

Maybe something like this would do:

import re

def lines_with_words(file, word1, word2):
"""Print all lines in file that have both words in it."""
for line in file:
if re.search(r"\b" + word1 + r"\b", line) and \
re.search(r"\b" + word2 + r"\b", line):
print line

Just call the function with a file object and two strings that
represent the words that you want to find in each line.

To match a word in regex you write "\bWRD\b".

I don't know if there is a better way of doing this, but I believe that
this should at least work.

Without using re, this may work (untested ;-):

def lines_with_words(file, word1, word2):
"""Print all lines in file that have both words in it."""
for line in file:
words = line.split()
if word1 in words and word2 in words:
print line

/Jean Brouwers

Rickard Lindberg wrote:
elrondrules (AT) gmail (DOT) com wrote:
Hi

Am pretty new to python and hence this question

I have file with an output of a process. I need to search this file one
line at a time and my pattern is that I am looking for the lines that
has the word 'event' and the word 'new'.

Note that i need lines that has both the words only and not either one
of them

how do i write a regexp for this or better yet shd i even be using
regexp or is there a better way to do this

thanks

Maybe something like this would do:

import re

def lines_with_words(file, word1, word2):
"""Print all lines in file that have both words in it."""
for line in file:
if re.search(r"\b" + word1 + r"\b", line) and \
re.search(r"\b" + word2 + r"\b", line):
print line

Just call the function with a file object and two strings that
represent the words that you want to find in each line.

To match a word in regex you write "\bWRD\b".

I don't know if there is a better way of doing this, but I believe that
this should at least work.

MrJean1 wrote:
def lines_with_words(file, word1, word2):
"""Print all lines in file that have both words in it."""
for line in file:
words = line.split()
if word1 in words and word2 in words:
print line

This sounds better, it's probably faster than the RE version, Python
2.5 has a really fast strcontains__ method, done by effbot:

def lines_with_words(file, word1, word2):
"""Print all lines in file that have both words in it.
(word1 may be the less frequent word of the two)."""
for line in file:
if word1 in line and word2 in line:
print line

Bye,
bearophile

I see two potential problems with the non regex solutions.

1) Consider a line: "foo (bar)". When you split it you will only get
two strings, as split by default only splits the string on white space
characters. Thus "'bar' in words" will return false, even though bar is
a word in that line.

2) If you have a line something like this: "foobar hello" then "'foo'
in line" will return true, even though foo is not a word (it is part of
a word).

Rickard Lindberg wrote:

I see two potential problems with the non regex solutions.

1) Consider a line: "foo (bar)". When you split it you will only get
two strings, as split by default only splits the string on white space
characters. Thus "'bar' in words" will return false, even though bar is
a word in that line.

2) If you have a line something like this: "foobar hello" then "'foo'
in line" will return true, even though foo is not a word (it is part of
a word).

Here's a solution using re.split:

import re
import StringI

wordsplit = re.compile('\W+').split
def matchlines(fh, w1, w2):
w1 = w1.lower()
w2 = w2.lower()
for line in fh:
words = [x.lower() for x in wordsplit(line)]
if w1 in words and w2 in words:
print line.rstrip()

test = """1st line of text (not matched)
2nd line of words (not matched)
3rd line (Word test) should match (case insensitivity)
4th line simple test of word's (matches)
5th line simple test of words not found (plural words)
6th line tests produce strange words (no match - plural)
7th line "word test" should find this
"""
matchlines(StringIStringI(test), 'test', 'word')

Rickard Lindberg wrote:

I see two potential problems with the non regex solutions.

1) Consider a line: "foo (bar)". When you split it you will only get
two strings, as split by default only splits the string on white space
characters. Thus "'bar' in words" will return false, even though bar is
a word in that line.

2) If you have a line something like this: "foobar hello" then "'foo'
in line" will return true, even though foo is not a word (it is part of
a word).

Here's a solution using re.split:

import re
import StringI

wordsplit = re.compile('\W+').split
def matchlines(fh, w1, w2):
w1 = w1.lower()
w2 = w2.lower()
for line in fh:
words = [x.lower() for x in wordsplit(line)]
if w1 in words and w2 in words:
print line.rstrip()

test = """1st line of text (not matched)
2nd line of words (not matched)
3rd line (Word test) should match (case insensitivity)
4th line simple test of word's (matches)
5th line simple test of words not found (plural words)
6th line tests produce strange words (no match - plural)
7th line "word test" should find this
"""
matchlines(StringIStringI(test), 'test', 'word')

Rickard Lindberg, yesterday I was sleepy and my solution was wrong.

2) If you have a line something like this: "foobar hello" then "'foo'
in line" will return true, even though foo is not a word (it is part of
a word).

Right. Now I think the best solution is to use __contains__ (in) to
quickly find the lines that surely contains both substrings, then on
such possibly rare cases you can use a correctly done RE. If the words
are uncommon enough, such solution may be fast and reliable.
Using raw tests followed by slow and reliable ones on the rare positive
results of the first test is a solution commonly used in Computer
Science, that often is both fast and reliable. (It breaks when the
first test is passed too much often, or when it has some false
negatives).

Probably there are even faster solutions, scanning the whole text at
once instead of inside its lines, but the code becomes too much hairy
and probably it's not worth it.

Bye,
bearophile

18 Jan 2007 18:54:59 -0800, "Rickard Lindberg"
<ricli576 (AT) student (DOT) liu.sewrote:

>I see two potential problems with the non regex solutions.
>
>1) Consider a line: "foo (bar)". When you split it you will only get
>two strings, as split by default only splits the string on white space
>characters. Thus "'bar' in words" will return false, even though bar is
>a word in that line.
>
>2) If you have a line something like this: "foobar hello" then "'foo'
>in line" will return true, even though foo is not a word (it is part of
>a word).

1) Depends how you define a 'word'.

2) This can be resolved with

templine = ' ' + line + ' '
if ' ' + word1 + ' ' in templine and ' ' + word2 + ' ' in templine:

Dan

Daniel Klein wrote:

2) This can be resolved with

templine = ' ' + line + ' '
if ' ' + word1 + ' ' in templine and ' ' + word2 + ' ' in templine:

But then you will still have a problem to match the word "foo" in a
string like "bar (foo)".

Fri, 19 Jan 2007 22:57:37 -0800, Rickard Lindberg wrote:

Daniel Klein wrote:

>2) This can be resolved with
>>
>templine = ' ' + line + ' '
>if ' ' + word1 + ' ' in templine and ' ' + word2 + ' ' in templine:

But then you will still have a problem to match the word "foo" in a
string like "bar (foo)".

That's a good point for a general word-finder application, but in the case
of the Poster's problem, it depends on the data he is dealing
with and the consequences of errors.

If the consequences are serious, then he may need to take extra
precautions. But if the consequences are insignificant, then the fastest,
most reliable solution is probably a simple generator:

def find_new_events(text):
for line in text.splitlines():
line = line.lower() # remove this for case-sensitive matches
if "event" in line and "new" in line:
yield line

To get all the matching lines at once, use list(find_new_events(test)).

This is probably going to be significantly faster than a regex.

So that's three possible solutions:

(1) Use a quick non-regex matcher, and deal with false positives later;

(2) Use a slow potentially complicated regex; or

(3) Use a quick non-regex matcher to eliminate obvious non-matches, then
pass the results to a slow regex to eliminate any remaining false
positives.

Which is best will depend on the P.'s expected data. As always, resist
the temptation to guess which is faster, and instead use the timeit module
to measure it.

egchow do i write a regexp for this or better yet shd i even be using
egcregexp or is there a better way to do this
"A team of engineers were faced with a problem; they decided to handle
it with regular expressions. Now they had two problems"

Regular expressions are not always the best solution. have
pointed out how it can work with "if word in line", this approach will
do if you're dealing with simple cases.

Take a look at this discussion, it is very informative: