What kind of post is this?
I do not see that anything was added at all. Give us all a break - don't
bother - whatever your intentions.
At 06:35 PM 7/24/2005, $Bill Luebkert wrote:
>John Deighan wrote:
At 02:20 PM 7/24/2005, Ed Chester wrote:
>
>
>>John Deighan::
>>
Is there a safe way to compare 2 floating point numbers in Perl? [snip]
My debugger says that they're both '630.24' [snip]
However, the == test fails and the != test succeeds
>>
>>can you post code with the comparison == that fails ?
>>if the debugger says they're the same, they're very very probably the same.
>>are you sure the variable (or whatever) you're giving to == are
>>really what you
>>want them to be?
>>there are lots of ways to compare numbers, right down to looping over
the bits
>>and logically
>>XNRing them.
>
>
Sorry about the lack of sample code, but I know that people who work
with floating point numbers know about this problem, and I was
wondering what the best solution was. Here is sample code with
output. Note that I'm not formatting the output or rounding or
anything - just printing out the contents of the 2 variables.
my $sum1 = -237.15;
my $sum2;
$sum2 += -26.35;
$sum2 += -26.35;
$sum2 += -26.35;
$sum2 += -26.35;
$sum2 += -26.35;
$sum2 += -26.35;
$sum2 += -26.35;
$sum2 += -26.35;
$sum2 += -26.35;
print("sum1 = $sum1\n");
print("sum2 = $sum2\n");
if ($sum1 == $sum2) {
>
>You could try something like:
>
if (abs ($sum1 - $sum2) < .0001) {
print("EQUAL\n");
}
else {
print("NT EQUAL\n");
}
UTPUT:
sum1 = -237.15
sum2 = -237.15
NT EQUAL
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