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  • MITM on 3TDES and why is the effective key lenght 112 bits

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    Can anyone explain how the MITM works on 3TDES (three distinct keys)?
    I am typically interested in finding out why 3TDES has effective
    key-length of 112-bit
    In Peace,
    Saqib Ali
  • No.1 | | 353 bytes | |

    "Saqib Ali" <docbook.xml@gmail.comwrote in news:1157590926.262613.165900
    @e3g2000cwe.googlegroups.com:

    Can anyone explain how the MITM works on 3TDES (three distinct keys)?

    I am typically interested in finding out why 3TDES has effective
    key-length of 112-bit

    In Peace,
    Saqib Ali

    --

    Regards,
  • No.2 | | 160 bytes | |


    This has N explanation of how the MITM works or why the effective key
    lenght is reduced to 112 bits.
    In Peace,
    Saqib Ali
  • No.3 | | 104 bytes | |


    I think you should post your question to sci.crypt
    Kind regards
    Ludovic
  • No.4 | | 352 bytes | |


    Saqib Ali wrote:
    Can anyone explain how the MITM works on 3TDES (three distinct keys)?

    I am typically interested in finding out why 3TDES has effective
    key-length of 112-bit

    I wrote this ages ago for TechTarget, but it answers your question.

    <,289625,sid14_cid591441_tax292741,00.html>

    Jon

  • No.5 | | 989 bytes | |


    Jon wrote:
    <,289625,sid14_cid591441_tax292741,00.html>

    Thank you Sir. This is what I was looking for. :)

    Another good explanation was given by Mark Wooding on sci.crypt:

    So, triple DES involves three keys, K1, K2, K3. Write
    single-DESencryption with a key K and plaintext block x as E(K, x), and
    decryption as D(K, x). Triple DES encryption is E(K3, D(K2, E(K1,
    x))).

    Suppose you're given a plaintext block x and corresponding ciphertext
    y. For each possible K3, compute D(K3, y), and store the result in a
    table. This takes about 2^56 work, and uses 2^56 blocks of memory.

    Now, for each pair K1, K2, compute D(K2, E(K1, x)). If this matches
    one of the values in the table, find the corresponding K3, and test the
    whole key against some other plaintext/ciphertext pairs. Continue
    until you're done. This step takes no extra memory and requires 2^112
    time.

    In Peace,
    Saqib Ali

  • No.6 | | 201 bytes | |

    Saqib Ali wrote:
    --
    This has N explanation of how the MITM works or why the effective key
    lenght is reduced to 112 bits.
    It contains a link to the article about MITM.

Re: MITM on 3TDES and why is the effective key lenght 112 bits


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