Romram <sajjanharudit@gmail.comwrote:
I was asked to submit atleast 5 solutions for the following problem:

By Replacing/Adding or deleting only one character from the following
code snippet, make it print tttttttttttttttttttt (20 times)

#include<stdio.h>

int main()
{
int k, j=20;
for(k=0;k<j;k--)
printf("t);
printf("\n");
return 0;
}

I assume you forget the closing quote in the first printf(). Please make
sure that the code you post actually is correct and compiles.

1. instead of for(k=0;k<j;k--) write for(k=0;k<j;j--)

2. instead of for(k=0;k<j;k--) write for(k=0;-k<j;k--)

3.instead of for(k=0;k<j;k--) write for(k=0;k+j;k--)

Can anyone suggest me 2 more solutions?

instead of for(k=0;k<j;k--) write for(k=0;k<j;j-- )
instead of for(k=0;k<j;k--) write for(k=0;k<j;j-- )

et cetera. If this is not considered a correct answer, the question
should have been more precise.

Can anyone suggest me 2 more solutions?
instead of for(k=0;k<j;k--) write for(k=0;k<j;j-- )
instead of for(k=0;k<j;k--) write for(k=0;k<j;j-- )
et cetera. If this is not considered a correct answer, the question
should have been more precise.

Ico <usenet@zevv.nlwrote:
Romram <sajjanharudit@gmail.comwrote:
>I was asked to submit atleast 5 solutions for the following problem:
>>
>By Replacing/Adding or deleting only one character from the following
>code snippet, make it print tttttttttttttttttttt (20 times)
>>
>#include<stdio.h>
>>
>int main()
>{
>int k, j=20;
>for(k=0;k<j;k--)
>printf("t);
>printf("\n");
>return 0;
>}
>
I assume you forget the closing quote in the first printf(). Please make
sure that the code you post actually is correct and compiles.
>
>1. instead of for(k=0;k<j;k--) write for(k=0;k<j;j--)
>>
>2. instead of for(k=0;k<j;k--) write for(k=0;-k<j;k--)
>>
>3.instead of for(k=0;k<j;k--) write for(k=0;k+j;k--)
>>
>Can anyone suggest me 2 more solutions?
>
instead of for(k=0;k<j;k--) write for(k=0;k<j;j-- )
instead of for(k=0;k<j;k--) write for(k=0;k<j;j-- )

Ehm, no those are wrong ofcourse, I changed *and* inserted, which is
against the rules. I should sit on my hands before I type.

Romram <sajjanharudit@gmail.comwrote:
I was asked to submit atleast 5 solutions for the following problem:

By Replacing/Adding or deleting only one character from the following
code snippet, make it print tttttttttttttttttttt (20 times)

#include<stdio.h>

int main()
{
int k, j=20;
for(k=0;k<j;k--)
printf("t);
printf("\n");
return 0;
}

I came up with 3 solutions which were

1. instead of for(k=0;k<j;k--) write for(k=0;k<j;j--)
2. instead of for(k=0;k<j;k--) write for(k=0;-k<j;k--)
3.instead of for(k=0;k<j;k--) write for(k=0;k+j;k--)

Can anyone suggest me 2 more solutions?

I have reason to believe you have already found the only three possible
solutions. I couldn't think of any more than the ones you already
stated, so I have just tried a brute-force search of all possible
replaces/additions/deletions of all possible characters at all possible
locations.

I'm interested in any other solutions that I might have missed.

Ico

Romram wrote:
I was asked to submit atleast 5 solutions for the following problem:

By Replacing/Adding or deleting only one character from the following
code snippet, make it print tttttttttttttttttttt (20 times)

#include<stdio.h>

int main()
{
int k, j=20;
for(k=0;k<j;k--)
printf("t);
printf("\n");
return 0;
}

I came up with 3 solutions which were

1. instead of for(k=0;k<j;k--) write for(k=0;k<j;j--)

2. instead of for(k=0;k<j;k--) write for(k=0;-k<j;k--)

3.instead of for(k=0;k<j;k--) write for(k=0;k+j;k--)

Can anyone suggest me 2 more solutions?

Clearly some sort of homework. The canonical for loop

for (k = 0; k < j; ++k)

otherwise the loop almost infinite. The snippet is broken in at least
two places and cannot be fixed with one change (as far as I can tell).

Please compile these things into small programs before posting here.

Ico wrote:
Romram <sajjanharudit@gmail.comwrote:
>I was asked to submit atleast 5 solutions for the following problem:
>>
>By Replacing/Adding or deleting only one character from the following
>code snippet, make it print tttttttttttttttttttt (20 times)
>>
>#include<stdio.h>
>>
>int main()
>{
>int k, j=20;
>for(k=0;k<j;k--)
>printf("t);
>printf("\n");
>return 0;
>}
>>
>I came up with 3 solutions which were
>>
>1. instead of for(k=0;k<j;k--) write for(k=0;k<j;j--)
>2. instead of for(k=0;k<j;k--) write for(k=0;-k<j;k--)
>3.instead of for(k=0;k<j;k--) write for(k=0;k+j;k--)
>>
>Can anyone suggest me 2 more solutions?
>
I have reason to believe you have already found the only three possible
solutions. I couldn't think of any more than the ones you already
stated, so I have just tried a brute-force search of all possible
replaces/additions/deletions of all possible characters at all possible
locations.

I'm interested in any other solutions that I might have missed.

add a single `-' to for(k=0;k<j;k--): for(k=0;-k<j;k--)
^

Pedro Graca <hexkid@dodgeit.comwrote:
Ico wrote:
>Romram <sajjanharudit@gmail.comwrote:
I was asked to submit atleast 5 solutions for the following problem:

By Replacing/Adding or deleting only one character from the following
code snippet, make it print tttttttttttttttttttt (20 times)

#include<stdio.h>

int main()
{
int k, j=20;
for(k=0;k<j;k--)
printf("t);
printf("\n");
return 0;
}

I came up with 3 solutions which were

1. instead of for(k=0;k<j;k--) write for(k=0;k<j;j--)
2. instead of for(k=0;k<j;k--) write for(k=0;-k<j;k--)
3.instead of for(k=0;k<j;k--) write for(k=0;k+j;k--)

Can anyone suggest me 2 more solutions?
>>
>I have reason to believe you have already found the only three possible
>solutions. I couldn't think of any more than the ones you already
>stated, so I have just tried a brute-force search of all possible
>replaces/additions/deletions of all possible characters at all possible
>locations.
>>
>I'm interested in any other solutions that I might have missed.
>
add a single `-' to for(k=0;k<j;k--): for(k=0;-k<j;k--)
^

Is that not the same as P's solution #2 ?

Ico wrote:
Romram <sajjanharudit@gmail.comwrote:
>I was asked to submit atleast 5 solutions for the following problem:
>>
>By Replacing/Adding or deleting only one character from the following
>code snippet, make it print tttttttttttttttttttt (20 times)
>>
>#include<stdio.h>
>>
>int main()
>{
>int k, j=20;
>for(k=0;k<j;k--)
>printf("t);
>printf("\n");
>return 0;
>}
>>
>I came up with 3 solutions which were
>>
>1. instead of for(k=0;k<j;k--) write for(k=0;k<j;j--)
>2. instead of for(k=0;k<j;k--) write for(k=0;-k<j;k--)
>3.instead of for(k=0;k<j;k--) write for(k=0;k+j;k--)
>>
>Can anyone suggest me 2 more solutions?
>
I have reason to believe you have already found the only three possible
solutions. I couldn't think of any more than the ones you already
stated, so I have just tried a brute-force search of all possible
replaces/additions/deletions of all possible characters at all possible
locations.

I'm interested in any other solutions that I might have missed.

My last post was a repeated solution. Sorry.

If you don't mind UB (decrementing k past INT_MIN) or using an
unprototyped function or waiting for the program to go through all the
negative values of the int type

instead of printf("t"); write pruntf("t"); and link with a library that
defines

int pruntf(char const * t) {
static int n = 20;
if (n) {
;
printf("%s", t);
}
return 0;
}

Romram <sajjanharudit@gmail.comwrote:
I was asked to submit atleast 5 solutions for the following problem:

By Replacing/Adding or deleting only one character from the following
code snippet, make it print tttttttttttttttttttt (20 times)

#include<stdio.h>

int main()
{
int k, j=20;
for(k=0;k<j;k--)
printf("t);
printf("\n");
return 0;
}

I came up with 3 solutions which were

1. instead of for(k=0;k<j;k--) write for(k=0;k<j;j--)
2. instead of for(k=0;k<j;k--) write for(k=0;-k<j;k--)
3.instead of for(k=0;k<j;k--) write for(k=0;k+j;k--)

Can anyone suggest me 2 more solutions?

It's been a few days now, did you found any alternatives yet ?

Ico