William Xu wrote:
Hi, all,
This piece of code used to work well. i guess the error occurs after
some upgrade.
import urllib
from BeautifulSoup import BeautifulSoup
url = 'http://www.google.com'
port = urllib.urlopen(url).read()
soup = BeautifulSoup()
soup.feed(port)
Traceback (most recent call last):
File "<stdin>", line 1, in ?
File "/usr/lib/python2.3/sgmllib.py", line 94, in feed
Look at the traceback: you're not calling BeautifulSoup module! In
fact, there is no feed method in the current BeautifulSoup
documentation. Maybe it used to work well, but now it's definitely
going to fail. As I understand documentation you need to write
soup = BeautifulSoup(port)

"Serge " <S (AT) gmail (DOT) comwrites:

[]

Look at the traceback: you're not calling BeautifulSoup module! In
fact, there is no feed method in the current BeautifulSoup
documentation. Maybe it used to work well, but now it's definitely
going to fail. As I understand documentation you need to write

soup = BeautifulSoup(port)

Ah, yes ! Things change ! :-)

BeautifulSoup feed() method used to exist before 3.0.0, and was left
over to SGMLParser later. As explained in the changlog,

Release 3.0.0 (2006/05/28), "Who would not give all else for two p"

Beautiful Soup no longer implements a feed method. You need to pass a
string or a filehandle into the soup constructor, not with feed after
the soup has been created. There is still a feed method, but it's the
feed method implemented by SGMLParser and calling it will bypass
Beautiful Soup and cause problems.

Thanks for all the help !