"serrand" <xavier.serrand@free.frwrote in message
news:43dccd11$0$29227$8fcfb975@news.wanadoo.fr
Could someone tell me a beautiful way to exit from a switch and a loop in
one statement
without using a goto and if possible without using an auxiliary
variable as i did
int res;
while (1)
{
res = 0;
if ((i = msgrcv (msqid, &rq_resa, SZ_MsgSrcResa, pid(), 0) == -1)
{
aff_erreurs ("msgrcv", "Error when recieving message : %d",
errno);
continue;
}
if (strcasecmp (rq_resa.mess,"admin"))
printf ("Admin d'ont manage bad formatted messages\n");
else
switch (rq_resa.rep)
{
case 'q':
res = working_q();
manage_error (res);
break;
case 'f':
res = working_f();
manage_error (res);
break;
default:
printf ("This function is not yet implemented\n");
}
if (res) break;
}
all ideas welcome,
Xavier
Like Sosman, I think 'continue' is the way to go. All loopable cases hit a
'continue' and all exitable cases hit a 'break' 'break'. Also, there is no
use of a temporary variable 'res'. Unfortunately, without the temporary
variable, manage_error() always gets called. Also, it's 'receiving', the
'i' and 'e' are switched. Also, it's "doesn't" not "d'ont".
while (1)
{
if ((i = msgrcv (msqid, &rq_resa, SZ_MsgSrcResa, pid(), 0) == -1)
{
aff_erreurs ("msgrcv", "Error when receiving message : %d",
errno);
continue;
}
if (strcasecmp (rq_resa.mess,"admin"))
{
printf ("Admin doesn't manage bad formatted messages\n");
continue;
}
else
switch (rq_resa.rep)
{
case 'q':
manage_error (working_q());
break;
case 'f':
manage_error (working_f());
break;
default:
printf ("This function is not yet implemented\n");
continue;
}
break;
}
Rod Pemberton